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Find the values of the remaining five trigonometric functions of theta with the given constaint (((( need to see how to do it ))))?
sin theta=-1/2
Find all solution of the equation in the interval 2cos^2 x -cosx=1 the answer is (0, 2pie/3 4pie/3)
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- ted sLv 74 years ago
the reference triangle for Θ is < ± √3 , - 1 , 2 > depending upon which quadrant Θ is in
w = cos x leads to 2 w² - w - 1 = 0 ====> [ 2 w + 1 ] [ w - 1 ] = 0 ===> cos Θ = 1 or - 1 / 2...if 1 then x = 0 , if - 1 / 2 the x = 2π / 3 or 4π / 3 { 2nd & 3rd quadrants }................and it is pi , not pie
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