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I have filled a bag with differently colored ping-pong balls.?

There are twenty balls in the bag. Twelve are white, six are orange and two are pink. When I draw a ball from the bag, I remove it. What is the probability that my first draw is a white ball and my second is not?

2 Answers

Relevance
  • 4 years ago

    (12/20)(8/19) = 24/95

  • ?
    Lv 7
    4 years ago

    First draw P(white) = 12/20 = 3/5

    Second draw P(not white) = 8/19

    P = 3/5 * 8/19 = 24/95

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