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? asked in Science & MathematicsChemistry · 4 years ago

You titrate 0.578 g of impure aspirin with 27.83 mL of 0.865 M NaOH. What is the molar mass of this sample? Show work.?

Thank you in advance!

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  • Roger the Mole
    Lv 7
    4 years ago
    Favorite Answer

    Supposing NaOH reacts with aspirin in equimolar quantities.

    (0.02783 L) x (0.865 mol/L NaOH) x (1 mol aspirin / 1 mol NaOH) = 0.02407 mol aspirin

    (0.578 g) / (0.02407 mol) = 24.0 g/mol

    [Although I fail to see the point to calculating the molar mass of a mixture like this.]

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