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Vector Total Displacement Question?

A bug starts at a position given by (42,28)then moves to position (29,36) then moves to position (11,12). Determine the magnitude and direction of the bug's displacement? Please show steps

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  • 4 years ago

    Draw a diagram (xy axes) and mark the given points A, B and C.

    Draw an arrow from the start point A(42, 48) to the end point C(11,12). This arrow is the displacement. Where point B is doesn't matter.

    From Pythagoras:

    |AC|² = (42-11)² + (28-12)²

    . . . . .= 31² + 16²

    . . . . = 1217

    |AC| =√1217

    . . . . = 34.9m (that's the magnitude)

    If you imagine a new set of xy axes drawn so the origin is the start point point (A), the direction of AC is into the 3rd quadrant.

    AC is an angle θ anticlockwise from the new -x axis where

    tanθ = 16/31 = 0.5161

    θ = tan⁻¹0.5161 = 27°

    So, measured clockwise from the +x axis, the direction is 180° + 27° = 207° (which is the usual way to give the direction).

    Adding 2 vectors this way is an essential skill for many problems. Try the video in the link.

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