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[Grade 12 ~ Momentum] How is acceleration calculated for in this question?
'Thor throws his 45 kg hammer at the Incredible Hulk at 75 m/s. The Hulk catches the hammer and manages to stop it over a distance of 0.80 m.
A) determine the acceleration of the hammer as the Hulk stops it.
2 Answers
- ArgentLv 74 years agoFavorite Answer
Use the general equation for velocity in terms of acceleration and displacement: v² = v₀² + 2ax.
Solve this for a: a = (v² - v₀²)/(2x).
Here, v = 0 m/s (when the Hulk stops Mjölnir); v₀ = 75 m/s; x = 0.80 m. Substitute:
(0 m²/s² - 5625 m²/s²) / (2(0.80 m)) = -3515.625 m/s². With 2 significant figures, this is -3500 m/s².
(Note that the mass of the hammer is irrelevant here.)
- Anonymous4 years ago
m.A.D = W = ½ m.(0 - V○²) ← theorem of the kinetic energy
A = -½ V○²/D = -0.5*75^2/0.8 = -3.52 km/s²
