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Grace
Grace asked in Science & MathematicsPhysics · 4 years ago

Physics Projectile Question?

A soccer ball, kicked from ground level at an angle of 73.0° above horizontal, is in the air for 4.80 s. What was its initial speed just after it was kicked? Ignore air resistance.

3 Answers

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  • electron1
    Lv 7
    4 years ago

    Let v be the initial velocity.

    Initial vertical velocity = v * sin 73

    During one half of the time, the ball rises from the ground to its maximum height. As this happens, its vertical velocity decreases from the initial vertical velocity to 0 m/s at the rate of 9.8 m/s each second. Use the following equation to determine its initial vertical velocity.

    vf = vi – g * t

    0 = v * sin 73 – 9.8 * 2.4

    v * sin 73 = 23.52

    v = 23.52 ÷ sin 73

    The ball’s initial speed is approximately 24.6 m/s.

  • oubaas
    Lv 7
    4 years ago

    Vo*sin 73/g = 4.80/2

    Vo = 4.80*9.806/(2*0,956) = 24,62 m/sec

  • Steve
    Lv 7
    4 years ago

    From t/2 = V*sinΘ/g I get

    V = g*t/(2*sinΘ) = 24.6 m/s

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