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chemistry question?
A solid was found to be highly soluble in water. Treating separate portions of a solution of this solid with NaCl, NaBr, NaI, Na2SO4, Na2CO3, Na3PO4, NaOH, and Na2S produced no precipitates. Treatment of an aqueous solution of this solid with acid resulted in the formation of the foul-smelling gas H2S. This solid was:
a) (NH4)2S
b) KBr
c) Pb(NO3)2
d) Li2CO3
1 Answer
- Roger the MoleLv 74 years agoFavorite Answer
The only possibility that contains sulfur is (NH4)2S, so the answer must be a).
[Although the no-precipitate results are consistent with a NH4+ cation, too.]
