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Help on a physics problem (Centripetal acceleration)!?
"You are playing tetherball on the playground with your friend. Tetherball is played with two people and a ball attached to a rope. The other end of the string is attached to the top of a pole. The people hit the ball back and forth trying to wrap the rope around the pole.
Half a second after you hit the ball, the ball breaks from the rope, it is underground circular motion 1.50m away from the pole with a centripetal acceleration of 6.00 m/s^2 and has a height of 2.00m above the ground. How far from the pole is the ball when it lands on the ground?"
It s part of my exam prep book but it only gives the answer and I m not entirely sure how to lead up to the answer. Any help is appreciated!
1 Answer
- 4 years ago
Use ac=v^2/r to get the velocity of the ball initially, then solve the problem as a projectile motion question (split the motion into x and y components, use d=vit+1/2at^2 to solve for t in the y direction then use v=d/t to solve for d in the x direction). If i did it all right the answer should be 1.92m.
Source(s): Grade 11 physics.
