Determine delta H for the reaction CS2+3Cl2 to CCl4+S2Cl2. Algebraically combine the necessary equations. Show work. Thanks in advance!!!?

You need "CS2" on the left. The only given equation that mentions CS2 is (1), so copy (1):

CS2 + 3 O2 → CO2 + 2 SO2, ΔH = -1077 kJ

You also need S2Cl2 on the right. The only given equation that mentions S2Cl2 is (2), so copy (2):

2 S + Cl2 → S2Cl2, ΔH = -58.2 kJ

Add the last two equations here:

CS2 + 3 O2 + 2 S + Cl2 → CO2 + 2 SO2 + S2Cl2, ΔH = -1135.2 kJ

Now you need to get rid of "2 S" on the left. The only given equation that mentions S that you haven't already used is (4), so multiply (4) by 2, then write it backwards:

2 SO2 → 2 S + 2 O2, ΔH = +593.6 kJ

Add the last two equations here:

CS2 + 3 O2 + 2 S + Cl2 + 2 SO2 → CO2 + 2 SO2 + S2Cl2 + 2 S + 2 O2, ΔH = -1135.2 kJ +593.6 kJ

Cancel like amounts on opposite sides of the arrow, and do the arithmetic for ΔH:

CS2 + O2 + Cl2 → CO2 + S2Cl2, ΔH = -541.6 kJ

Now you need to get rid of "CO2" on the right. The only given equation that mentions CO2 that you haven't already used is (6), so write (6) backwards:

CO2 → C + O2, ΔH = +393.5 kJ

Add the last two equations here:

CS2 + O2 + Cl2 + CO2 → CO2 + S2Cl2 + C + O2, ΔH = -541.6 kJ +393.5 kJ

Cancel like amounts on opposite sides of the arrow, and do the arithmetic for ΔH:

CS2 + Cl2 → S2Cl2 + C, ΔH = -148.1 kJ

Now you need CCl4 on the right. The two given reactions that mention CCl4 are (3) and (7). Notice that (7) includes COCl2. No other equation mentions COCl2, so if you choose (7) you are stuck with COCl2 because there is no other equation with which to get rid of it. So instead of (7), copy (3):

C + 2 Cl2 → CCl4, ΔH = -135.4 kJ

Add the last two equations here:

CS2 + Cl2 + C + 2 Cl2 → S2Cl2 + C + CCl4, ΔH = -148.1 kJ -135.4 kJ

Cancel like amounts on opposite sides of the arrow, combine Cl2 on the left,

and do the arithmetic for ΔH:

CS2 + 3 Cl2 → S2Cl2 + CCl4, ΔH = -283.5 kJ

And there's what you were looking for.