A population of bacteria doubles every 18 hrs. Initially the population of bacteria is 50.wat is the population the of bacteria after 60 hrs?

Let P₀ denote the inital population of bacteria. After 18 hours, the population will double. That is, the population after 18 hours will be P₀(2). After another 18 hours, this new population will double. That is, there will now be

[ P₀(2) ](2) or P₀(2)^2

Note that in general, the population of bacteria is given by

P(t) = P₀(2)^[t/18]

After 60 hours, the population will be

P(60) = 50(2)^[60/18] ≈ 504

doubles

every 18 hours

P=P*₀2^(t/18)

50*2^(60/18)

50*2^(10/3) ≈ 50×10.08 ≈ 504

50·2^(60/18) = 50·2^(10/3) ≅ 504

Does it double evenly over that time, or all reproduction occur at the 18 hour mark?