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Avery
Avery asked in Science & MathematicsMathematics · 4 years ago

Help!! i'm not sure what to do! Solve the following equation in the interval [0,2pi].?

Give the answer as a multiple of pi. Do not use decimal numbers. The answer should be a fraction or an integer. Note that pi is already included in the answer so you just have to enter the appropriate multiple. E.g. if the answer is pi/2 you should enter 1/2. If there is more than one answer enter them separated by commas.

(cos(t))^2=(3/4)

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  • Johnathan
    Lv 7
    4 years ago

    (cos(t))^2 = 3/4

    cos(t) = +/- sqrt(3/4) = +/- sqrt(3)/2.

    You have four possible answers; 1/6(pi), 5/6(pi), 7/6(pi), and 11/6(pi).

  • ted s
    Lv 7
    4 years ago

    cos t = ± √3 / 2 is taken 4 times in [ 0 , 2π ] ...π / 6 , 5π / 6 , 7π / 6 , 11 π / 6

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