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Chemistry Help!!?
.345 g of an unknown organic acid are dissolved in about 30ml of water. The solution is titrated with 15.85 ml of .138M sodium hydroxide. What is the molar mass of the unknown acid?
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- Roger the MoleLv 74 years ago
Supposing the unknown acid to be monoprotic:
(0.01585 L) x (0.138 mol/L NaOH) x (1 mol acid / 1 mol NaOH) = 0.0021873 mol acid
(0.345 g acid) / (0.0021873 mol acid) = 158 g/mol acid
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