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Chemistry Help?
The "air bags" in automobiles contain sodium azide, NaN3, which decomposes when activated by an electronic igniter to produce nitrogen gas that fills the bag. The unbalanced equation for this reaction is
___NaN3(s) => ___Na(s) + ___N2(g) How many liters of gas at 25 oC and 1.00 atm will be produced by 100.0 g of NaN3?
Please help thanks!
1 Answer
- Roger the MoleLv 73 years ago
2 NaN3(s) → 2 Na(s) + 3 N2(g)
( 100.0 g NaN3) / (65.00987 g NaN3/mol) x (3 mol N2 / 2 mol NaN3) = 2.30734 mol N2
V = nRT / P = (2.30734 mol) x (0.08205746 L atm/K mol) x (25 + 273) K / (1.00 atm) = 56.42 L N2