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f(x)=7sin(3πx−2)−3. The amplitude of this function is its period is its phase shift is and its vertical translation is?
f(x)=7sin(3πx−2)−3.
The amplitude of this function is
its period is
its phase shift is
and its vertical translation is
See attached photo i need to know how its done can you show the work with an explanation plesase!!??
ANYONE?? HELP!!
1 Answer
- ?Lv 73 years agoFavorite Answer
=>
f(x) = a sin b(x-h) + k
rewrite
f(x)=7sin(3πx−2)−3 = 7sin[3π(x-2/3π)] - 3
a=7, b=3π, h=2/(3π), k=-3
amplitude : 7
period = 2π/b = 2π/3π = 2/3
phase shift: 2/(3π), shift right
vertical shift: -3 (down 3)
