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Calculus Help?
Find the derivative of (9x+1)^3x.
I know the answer is (9x+1)^3x*(3ln(9x+1)+27x/(9x+1)).
Show work and explain thanks!
1 Answer
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- DWReadLv 73 years ago
Do you mean (9x+1)^3x, or (9x+1)^(3x) ?
Let y = (9x+1)³ˣ.
dy/dx = (9x+1)³ˣ[3ln(9x+1) + 27x/(9x+1)]
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