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The density of ice is 917 kg/m3. The density of sea water is 1025 kg/m3. A bear climbs onto some floating ice that has a volume of 4.76 m3.?
What is the weight of the heaviest bear that the ice can support without sinking completely beneath the water?
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- MorningfoxLv 73 years ago
The total mass of the ice is 4364.92 kg. The mass with the bear is 4364.92 kg + (Bear). We want the net density of ice + mass of Bear to be 1025 kg/m^3. So [ 4364.92 + (Bear) ] / 4.76 = 1025. You should be able to solve that.
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