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Physics question, please help! A steel section of pipeline had a length of 63.4 m and a temperature of 19.8 °C when it was installed.?

What is its change in length when the temperature drops to a frigid -38.2 °C?

1 Answer

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  • 3 years ago

    ΔL = Lo k ΔT

    k = 1.2x19^-5 K^-1

    ΔL = 63.4*1.2x10^-5*(-38.2 - 19.8) ~ - 0.04m

    L = Lo + ΔL = 63.36 m

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