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Calculus Help?
Compute the upper Riemann sum for the given function f(x)=x^2 over the interval x∈[−1,1] with respect to the partition P=[−1,−3/4,1/4,3/4,1].
Pls explain thx!!
1 Answer
- SqdancefanLv 73 years ago
Your sum will be the sum of products of the width of the interval and the maximum of the values of the function at the ends of the interval.
.. (-3/4 -(-1))*(1)^2 +(1/4 -(-3/4))*(-3/4)^2 +(3/4 -1/4)*(3/4)^2 +(1 -3/4)*(1)^2
.. = 1/4*1 +1*9/16 +1/2*9/16 +1/4*1
.. = 8/32 +18/32 +9/32 +8/32
.. = 43/32
