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How many ml of 1.80 M of hydrochloric acid are required to completely react with 30 grams of calcium hydroxide. Will give best answer...?
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- Roger the MoleLv 73 years agoFavorite Answer
Ca(OH)2 + 2 HCl → CaCl2 + 2 H2O
(30 g Ca(OH)2) / (74.0927 g Ca(OH)2/mol) x (2 mol HCl / 1 mol Ca(OH)2) / (1.80 mol HCl/L) = 0.450 L = 450 mL HCl
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