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CHEM HELP!!!!!?
Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl(aq), as described by the chemical equation
MnO2(s) + 4HCl(aq) --> MnCl(aq) + 2H2O(l) +Cl2(g)
How much MnO2(s) should be added to excess HCl(aq) to obtain 165 mL of Cl2(g) at 25 degrees celsius and 765 Torr??
1 Answer
- Roger the MoleLv 73 years ago
n = PV / RT = (765 Torr) x (0.165 L) / ((62.36367 L Torr/K mol) x (25 + 273) K) = 0.006792 mol Cl2
(0.006792 mol Cl2) x (1 mol MnO2 / 1 mol Cl2) x (86.93685 g MnO2/mol) = 0.590 g MnO2
