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The component of acceleration due to gravity down a smooth slope is 6.94 m s−2. Determine the angle the slope makes with the horizontal?
2 Answers
- oldschoolLv 73 years ago
The force causing acceleration down a slope = weight*sinΘ
This makes sense. At Θ = 0°, NONE of the weight causes sliding and sin0 = 0
At Θ = 90°, ALL of the weight causes sliding and sin90 = 1
Thus m*6.94 = m*9.8*sinΘ -----> 6.94/9.8 = sinΘ
asin(6.94/9.8) = Θ = 45.1°
- billrussell42Lv 73 years ago
Vertical, it would be 9.8 m/s²
sin θ = 6.94/9.8 = 0.708
θ = 45.1º
(to check if I have the right one of sin or cos, if the angle is 90º, sin θ would be 1, which is correct)
