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If this energy were used to vaporize water at 100 ∘C, how much water in liters could be vaporized?
(Assume that the density of water is 1.0 g/mL.) The heat of vaporization of water at 100 ∘C is 40.7 kJ/mole.
1 Answer
- billrussell42Lv 73 years agoFavorite Answer
"this energy" ? how much ?
heat of vaporization of water is 2256 kJ/kg
density of fresh water at 20C = 0.998 g/cm³
= 998 kg/m³ = 8.33 lb/gal = 62.1 lb/ft³
1 MJ can vaporize this much water:
1 MJ = 2256 kJ/kg x M kg
M = 1000/2256 kg
1000/2256 kg / 998 kg/m³ = 0.000444 m³
0.000444 m³ x 1000 L/m³ = 0.444 L
so 1 MJ can vaporize 0.444 L
