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nic
nic asked in Science & MathematicsChemistry · 3 years ago

A 155 g sample of an unknown substance was heated from 25.0°C to 40.0°C. In the process, the substance absorbed 5696 J of energy?

. What is the specific heat of the substance

1 Answer

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  • Adam
    Lv 7
    3 years ago
    Favorite Answer

    E = m c ΔT

    Specific heat, c = E / (m ΔT) = (5696 J) / [(155 g) × (40.0 - 25.0)°C] = 2.45 J/(g°C)

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