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A 6.21g piece of iron metal is heated from 21.6°C to 312.5°C. Calculate the heat absorbed (in J) by the metal.?
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- AdamLv 73 years ago
Refer to the webpage: https://www.engineersedge.com/materials/specific_h...
Specific heat of iron, c = 0.4605 J/(g°C)
Heat absorbed = m c ΔT = 6.21 × 0.4605 × (312.5 - 21.6) J = 832 J
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