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James
James asked in Education & ReferenceHomework Help · 3 years ago

Given:EFGH is an isosceles trapezoid, with legs Line HE and Line GF. EJ=x+5 JG=2x-1 HF=13 Find:EJ,JG,and HJ?

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  • texman
    Lv 7
    3 years ago

    In this type of trapezoid, the diagonals are congruent. So we can set the two diagonals equal to each other and solve for x.

    EG = HF = 13

    EG = EJ + JG (now substitute for these values)

    13 = (x + 5) + (2x - 1) (now solve for x)

    13 = 3x + 4

    3x = 9

    x = 3

    So EJ = x + 5 = 3 + 5 = 8

    and JG = 2x - 1 = 6 - 1 = 5

    and HJ = JG

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