Given Parallelogram ABCD, angle a=x degree, Angle D= (3x-4) Degree Find:m Angle D and m Angle C degree?

x + 3x - 4 = 180

4x = 184

x = 46

m<D = 3(46) - 4 = 134

m<C = m<A = 46

Assuming those vertices are listed in cyclic order, then angles A and D are adjacent, and angles A and C are opposite.

Adjacent angles in a parallelogram are supplementary, so:

m<A + m<D = 180

x + (3x - 4) = 180 .... substitute given angle measures

4x - 4 = 180 .... simplify and solve for x

4x = 184

x = 184/4 = 46

So m<A = x = 46 degrees and m<D = 3x-4 = 134 degrees.

Opposite angles in a parallelogram are congruent, so m<C = M<A = 46 degrees.

Angle D + Angle A = 180 Degree

3x - 4 + x = 180

4x - 4 = 180

4x = 184

X = 46 degrees = angle A

Angle D = (3*46) - 4 = 134 degree

Angle C = angle A = 46 degree