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? asked in Science & MathematicsPhysics · 3 years ago

Physics torque problem?

A uniform meterstick pivoted at its center has a 85 g mass suspended 21 cm from the pivot point.

(A) How far from the pivot should a 75 g be suspended to put the system in equilibrium?

(B) What mass would have to be suspended 40 cm from the pivot for the system to be in equilibrium?

1 Answer

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  • Whome
    Lv 7
    3 years ago
    Favorite Answer

    Moments (torques) about the pivot point must be of equal and opposite direction.

    A) 85(21) = 75x

    x = 23.8 cm on the opposite side of the pivot from the 85 g mass

    B 85(21) = m(40)

    m = 44.625 g

    I hope this helps.

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