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Physics question about sound and frequency. Dolphins emit clicks of sound for communication and echolocation.?
A marine biologist is monitoring a dolphin swimming in seawater where the speed of sound is 1527 m/s. When the dolphin is swimming directly away at 9.5 m/s, the marine biologist measures the number of clicks occuring per second to be at a frequency of 2460 Hz. What is the difference (in Hz) between this frequency and the number of clicks per second actually emitted by the dolphin?
If possible please include units and workings.
Happy to award a best answer.
1 Answer
- Randy PLv 73 years agoFavorite Answer
Why does the frequency change as the dolphin is swimming away? What effect is that? It's called the Doppler effect. Does that ring a bell? I'll bet it was just presented to you in class.
At that time you should have seen a formula like this: delta-f/f = v/v_sound.
The change in frequency delta-f divided by the original frequency f is equal to the ratio of the speed of the source or observer divided by the speed of sound.
So delta-f/2460 = 9.5/1527, or delta-f = change in frequency = what was asked for = 2460 * 9.5/1527