During a storm, a car traveling on a level horizontal road comes upon a bridge that has washed out. The driver must get to the other side,..?

Question

so he decides to try leaping the river with his car. The side of the road the car is on is 20.3 m above the river, while the opposite side is only 2.4 m above the river. The river itself is 64.0 m wide.

A) How fast, in m/s, should the car be traveling at the time it leaves the road in order to just clear the river and land safely on the opposite side?

B) What is the speed of the car just before it lands on the other side?

oubaas · Accepted Answer

Δh = 20.3-2.4 = 17.90 m 
falling time t = √2*Δh/g = √35.80/9.806 = 1.911 sec
minimum speed Vo = d/t = 64/1.911  = 33.50 m/sec
landing speed V = √Vo^2+2gΔh = √33.50^2+19.612*17.90 = 38.38 m/sec

Anonymous · Answer

As fast as it can.

Caoedhen · Answer

I don't know the speed, but there is no way in hell it is going to "land safely" after a 64 meter jump and dropping 19ish meters in the process.

Pure suicide.

Anonymous · Answer

You need the cars weight horsepower and torque to calculate the answer.

Trending News

During a storm, a car traveling on a level horizontal road comes upon a bridge that has washed out. The driver must get to the other side,..?

4 Answers