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Kylie
Kylie asked in Science & MathematicsChemistry · 3 years ago

Do you know how to Calculate the mass of 2.314x10^29 molecules of ammonium carbonate?

I am having a difficult time setting up the problem.

All I know is that this is a three step problem.

I start by dividing the 2.314x10^29 molecules into ???

And ammonium carbonate is (NH4)2CO3

3 Answers

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  • billrussell42
    Lv 7
    3 years ago

    ammonium carbonate is (NH4)2CO3

    start by calculating the molecular number of that

    2 nitrogen x 14 = 28

    8 H x 1 = 8

    1 C x 12 = 12

    3 O x 16 = 48

    total = 96 grams/mole

    Avogadro constant : 6.022e23 molecules/mole

    the rest is dimensional analysis

    2.314x10^29 molecules / 6.022e23 molecules/mole = 384000 mole

    96 grams/mole x 384000 mole = 3.69e7 grams o3 3.67e4 kg or 36700 kg

  • ?
    Lv 7
    3 years ago

    No, I don't, been out of school for 55 plus years and I took advanced chemistry too.

  • Roger the Mole
    Lv 7
    3 years ago

    (2.314 x 10^29 molecules) / (6.02214 x 10^23 molecules/mol) x (96.0858 g (NH4)2CO3/mol) = 36920852 g =

    36921 kg (NH4)2CO3

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