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object has a charge of +25μC, the instrument indicates the electric force on it is 20μN east. magnitude + direction of the electric field?
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- RealProLv 73 years agoFavorite Answer
Force on a charge q in electric field of magnitude E is q*E and points in the direction of the field for a positive charge, and opposite it for a negative charge.
E = F/q = 4/5 N/C east.
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