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Jake asked in Science & MathematicsPhysics · 3 years ago

Fluid dynamics?

A pump is used to empty the water from one cylindrical tank into another. The supply tank is 90 cm in diameter, the bottom of the tank is 1.2 m above the pump and the tank is originally filled to a level of 1.5 m. The empty receiving tank is 1.15 m in diameter and the bottom of the tank is 4 m above the pump. Neglecting losses, determine the work required to transfer the water

1 Answer

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  • oubaas
    Lv 7
    3 years ago

    water volume V = 0.7854*9^2*15 = 954.26 liters

    h1 = 4.00 m

    h2 = (0,9^2*1.5/1.15^2)/2 = 0.46 m

    h3 = (1.2*0.30)/2 = 0.45 m

    h = h1+h2+h3 = 4.91 m

    work = m*g*h = 954.26*9.806*4.91/1000 ≈ 46.0 kjoule

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