Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

What are the Cartesian coordinates of a point on the parabola y^2 = -16x, corresponding to the parameter t = 1/2 ? Is this point unique ?

Update:

What are the Cartesian Co-ordinates of a point, on the parabola y^ = -16x, having the parameter t = 1/2 ?

Is this point unique ?

2 Answers

Relevance
  • 3 years ago
    Favorite Answer

    Unless you have a specific pair of parameterized functions, there is no way to get a single unique point.

    y² = -16x

    For example, here's one way to parameterize the parabola:

    x = -4t²

    y = -8t

    Then for t=½:

    x = -4(½²) = -1

    y = -8(½) = -4

    But here is another way to parameterize the same parabola:

    x = -t²

    y = 4t

    Then for t=½

    x = -1/4

    y = 2

  • ted s
    Lv 7
    3 years ago

    since no parametric equations are given then no parameter exists

Still have questions? Get your answers by asking now.