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HELP WITH MY TRIG HW: De Moivre’s Theorem *Best Answer Awarded*?
PLEASE Help! Best answer awarded.
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- cmcsafeLv 73 years ago
Express the given number (a+ib) in polar form
ρ=√(a²+b²)=√(3+1²)=2
cosθ=a/ρ=-√3/2
sinθ=b/ρ==1/2
hence θ=5π/6
(-√3+i)=ρ(cosθ+isinθ)=
=2(cos(5π/6)+isin(5π/6))=
=2cis(5π/6)
from De Moivre
(-√3+i)³=2³cis(5π/2)=8*cis(π/2)=8i
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