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- Mike GLv 73 years agoFavorite Answer
3rcosθ+5rsinθ = -3
r(3cosθ+5sinθ) = -3
r = -3/(3cosθ+5sinθ)
see graph
- 3 years ago
x = r * cos(t)
y = r * sin(t)
x^2 + y^2 = r^2
That's all you need to remember
3x + 5y + 3 = 0
3 * r * cos(t) + 5 * r * sin(t) + 3 = 0
r * (3cos(t) + 5sin(t)) + 3 = 0
r * (3cos(t) + 5sin(t)) = -3
r = -3 / (3 * cos(t) + 5 * sin(t))
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