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PLEASE HELP WITH TRIG HW: Angle-Angle-Triangles *Best answer guaranteed*?
This is what I got but im not sure if I am correct.
Best answer guaranteed.
1 Answer
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- cmcsafeLv 73 years ago
A=180°-B-C=180°-33°-71°=76°
Apply sin theorem
i) b
a/sinA=b/sinB ⇒ b=a*sin33°/sin76°=10*0.545/0.97= 5.6
ii) c
a/sinA=c/sinC ⇒ c=a*sin71°/sin76°=10*0.946/0.97= 9.7
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