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PLEASE HELP WITH TRIG HW: Angle-Angle-Triangles *Best answer guaranteed*?

This is what I got but im not sure if I am correct.

Best answer guaranteed.

Attachment image

1 Answer

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  • 3 years ago

    A=180°-B-C=180°-33°-71°=76°

    Apply sin theorem

    i) b

    a/sinA=b/sinB ⇒ b=a*sin33°/sin76°=10*0.545/0.97= 5.6

    ii) c

    a/sinA=c/sinC ⇒ c=a*sin71°/sin76°=10*0.946/0.97= 9.7

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