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student moves carton of books with mass of 120 kg, μs is 0.42, and μk is 0.30. what horizontal force will he push to get the carton moving?

2 Answers

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  • 3 years ago

    The force must exceed F = kN = .42*120*9.8 = 493.9 N. ANS.

  • 3 years ago

    Use the coefficient of static friction to determine the force required to start the carton in motion

    F=μs*Normal force = μs*mass*gravity (assuming the carton is on a horizontal surface)

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