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bullet is shot at angle of 27° above horizontal. In air for 12.2s. it strikes ground 340 m from the shooter. initial y-velocity of bullet?
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- billrussell42Lv 73 years ago
range of object projected at an angle θ
R = (V²/g)sin(2θ)
V is initial velocity in m/s
g is the acceleration of gravity 9.8 m/s²
Vx = Vcos27
Vx = 340/12.2 m/s
Vcos27 = 340/12.2 = 27.87
V = 27.87 / cos27 = 31.28 m/s
Vy = 31.28 sin 27 = 14.2 m/s
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