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cannon launched at angle of 30°, cannon travels horizontal dist of 300 m before hits ground. what other angle would cannon travel same range?
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- billrussell42Lv 73 years agoFavorite Answer
range of object projected at an angle θ
R = (V²/g)sin(2θ)
V is initial velocity in m/s
g is the acceleration of gravity 9.8 m/s²
300 = (V²/g)sin(2•30) = (V²/g)sin(60)
basically what angle has the same value for the sine as 60º and that is 120º, and half that is 60º
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