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Start from rest,10kg block slides 3m down frictionless ramp (30° from floor) to bottom.Block slides another 5m on the floor before stopping?
Find Speed of the block at bottom of ramp & coefficient of friction between block & floor.
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- oubaasLv 73 years agoFavorite Answer
Vf = √2*g*ℓ*sin 30° = √2*ℓ*g*0.5 = √g*ℓ = √9,806*3 = 5.424 m/sec
m/2*Vf^2 = m*g*μ*d
since Vf^2 = g*ℓ , then :
m/2*g*ℓ = m*g*μ*d
mass m and gravity g cross
μ = ℓ/(2*d) = 3/(2*5) = 0.3
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