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PLEASE HELP W/ MY TRIG HW: Graph the parabola *BEST ANSWER AWARDED*?
Solve this for me please. Best answer awarded.
2 Answers
Relevance
- tcLv 73 years ago
=>
2y^2+20y-x+48 = 0
x = 2y^2+20y+48
x = 2[y^2+10y+24]
x = 2[(y+5)^2-25+24]
x = 2(y+5)^2 - 2
vertex: (-2, -5) => open right
also,
x = 2[y^2+10y+24] = 2(y+4)(y+6)
y-int. (0, -4), (0, -6)
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