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PLEASE HELP W/ MY TRIG HW: Graph the parabola *BEST ANSWER AWARDED*?

Solve this for me please. Best answer awarded.

Attachment image

2 Answers

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  • tc
    Lv 7
    3 years ago

    =>

    2y^2+20y-x+48 = 0

    x = 2y^2+20y+48

    x = 2[y^2+10y+24]

    x = 2[(y+5)^2-25+24]

    x = 2(y+5)^2 - 2

    vertex: (-2, -5) => open right

    also,

    x = 2[y^2+10y+24] = 2(y+4)(y+6)

    y-int. (0, -4), (0, -6)

    http://www.wolframalpha.com/input/?i=2y%5E2%2B20y-...

  • alex
    Lv 7
    3 years ago

    2(y+5)^2 = x-2

    side parabola with vertex (2,-5)

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