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Two carts are sitting on a frictionless track with a compressed spring between them. The sum of the masses of carts A and B is 1.5 kg.?
After the spring releases, Cart B has twice the speed of Cart A. What is the mass of each cart?
1 Answer
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- Anonymous3 years ago
mA + mB = 1.5
velocity of A is vA
velocity of B is -2vA (twice A's speed, opposite direction)
From conservation of momentum
mB.(-2vA) + mA,vA = 0
mA = 2mB
2mB + mB = 1.5
3mB = 1.5
mB = 0.5 kg
mA = 1.0 kg
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