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CONSERVED MOMENTUM QUESTION?
When riding your bicycle one day, you notice a toddler standing in the street in the path of a speeding car. Still on your bike, you ride in front of the car, grabbing the toddler in one hand. If the combined mass of you and the bicycle is 95 kg, the toddler has a mass of 20 kg, and you are initially traveling at 25 m/s, what is your final velocity after you have grabbed the toddler?
3 Answers
- electron1Lv 73 years agoThis is a conservation of momentum problem. Initial momentum = 95 * 25 = 2,375 kg * m/s Total mass = 95 + 20 = 115 kg Final momentum = 115 * v 115 * v = 2,375 v = 2,375 ÷ 115 Rounded to two significant digits, your final velocity is approximately 21 m/s. I hope this is helpful for you. 
- Andrew SmithLv 73 years agoWhy are you riding your bike at 90km/hr in a 50km/hr zone? The car is the least of the threats to the child. If you grab one arm at this speed you will rip the arm clean off the child. So, superman, just slow down a bit. OK? For the numbers given. Momentum is conserved. Prior to the collision the momentum was 95 * 25 kg m/s After the collision the momentum must have the same value but the mass is now (95+20) = 115 so 95 * 25 = 115 * v v = 95 * 25 / 115 ~= 21 m/s 
- ?Lv 43 years agoMomentum before = Momentum after (ALL cases) This is an INELASTIC Collision In those cases: mass before * Velocity before = mass after * velocity after 95 kg * 25 m/s = (95 kg + 20 kg) * V after You do the math,. 



