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CONSERVED MOMENTUM QUESTION?

When riding your bicycle one day, you notice a toddler standing in the street in the path of a speeding car. Still on your bike, you ride in front of the car, grabbing the toddler in one hand. If the combined mass of you and the bicycle is 95 kg, the toddler has a mass of 20 kg, and you are initially traveling at 25 m/s, what is your final velocity after you have grabbed the toddler?

3 Answers

Relevance
  • 3 years ago

    This is a conservation of momentum problem.

    Initial momentum = 95 * 25 = 2,375 kg * m/s

    Total mass = 95 + 20 = 115 kg

    Final momentum = 115 * v

    115 * v = 2,375

    v = 2,375 ÷ 115

    Rounded to two significant digits, your final velocity is approximately 21 m/s. I hope this is helpful for you.

  • 3 years ago

    Why are you riding your bike at 90km/hr in a 50km/hr zone?

    The car is the least of the threats to the child.

    If you grab one arm at this speed you will rip the arm clean off the child. So, superman, just slow down a bit. OK?

    For the numbers given. Momentum is conserved.

    Prior to the collision the momentum was 95 * 25 kg m/s

    After the collision the momentum must have the same value but the mass is now (95+20) = 115

    so 95 * 25 = 115 * v

    v = 95 * 25 / 115 ~= 21 m/s

  • ?
    Lv 4
    3 years ago

    Momentum before = Momentum after (ALL cases)

    This is an INELASTIC Collision

    In those cases:

    mass before * Velocity before = mass after * velocity after

    95 kg * 25 m/s = (95 kg + 20 kg) * V after

    You do the math,.

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