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Mitra
Mitra asked in Science & MathematicsChemistry · 3 years ago

Chemistry stochiometry?

Update:

methanol (CH3OH) can be synthesized by the following reaction: CO(g)+2H2(g)--->CH3OH(g)

what volume (in liters) of hydrogen gas, at a temperature of 355 K and a pressure of 738 mm Hg, is required to synthesize 35.7g of methanol given an excess of CO gas?

Shouldn't we find out the limiting reagent first?

1 Answer

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  • Roger the Mole
    Lv 7
    3 years ago

    No, you are told that CO is in excess, so that means H2 is the limiting reactant.

    (35.7 g CH3OH) / (32.0419 g CH3OH/mol) x (2 mol H2 / 1 mol CH3OH) = 2.22833 mol H2 required

    V = nRT / P = (2.22833 mol) x (62.36367 L mmHg/K mol) x (355 K) / (738 mmHg) = 66.8 L H2

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