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Jamecia Brazil
Jamecia Brazil asked in Science & MathematicsChemistry · 3 years ago

PLEASE HELP WITH THIS CHEMISTRY QUESTION!!!?

. A gas sample in a Boyle’s law apparatus is compressed to a volume of 22.0 mL. If its original volume was 37.0 mL at 12,000 Pa, what is the new pressure of the gas sample. Show your calculations

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  • Roger the Mole
    Lv 7
    3 years ago
    Favorite Answer

    (12,000. Pa) x (37.0 mL / 22.0 mL) = 20,182 Pa

  • lenpol7
    Lv 7
    3 years ago

    Remember the Equation

    P(1)V(10 = P(2)V(2)

    Hence

    P(2) = P(1)V(1)/V(2)

    P(2) = 12,000 Pa x 37.0 mL / 22mL

    P(2) = 20,181. 8181... Pa

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