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A 15.0 kg bucket is lowered vertically by a rope in which there is 182 N of tension so what is the magnitude of acceleration of the bucket.?
2 Answers
- ?Lv 62 years ago
Given,
The tension in the rope (T) = 182N
The mass of the bucket (m) = 15kg
The acceleration due to gravity (g) = 9.8 m/sec²
According to Newton’s second law of motion:-
mg – T = ma
mg – ma = T
m[g-a] = T
Tension (T) = m(g-a) = 15[9.8 – a]
182N = 15kg [9.8 m/sec² - a]
182/15 = (9.8 – a)
12.13 = 9.8 – a
Acceleration (a) = 12.13 – 9.8 = 2.33 m/sec²
∴ Acceleration (a) = 2.33 m/sec².
Source(s): http://myrank.co.in/ - AshLv 72 years ago
F(net) = 182 - (15 * 9.8)
ma = 182 - (15 * 9.8)
a = [182 - (15 * 9.8)] / m
a = [182 - (15 * 9.8)] / 15
a = 2.33 m/s²
