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Can someone help with any of these math questions?
1 Answer
- ?Lv 72 years ago
15.
Mass = T tonnes = ? kg (use formula shown)
Density = 2.5g/cm³ = 2.5g/cm³ * (1kg/1000g) * (100cm/m)³ = ?? kg/m³
Density = Mass/Volume
Volume = Mass/Density = (? kg) / (?? kg/m³) = ??? m³
13.
a₁ = a
a₄ = a + 3d = ka
a₇ = a + 6d = 9a
Solve for k
Hint: a₇−a₄ = 3d = a₄−a₁ → 9a−ka = ka−a
23.
Draw a line from O to top of circle, and from O to point where circle and rectangle intersect.
You now have 3 shapes:
• 1/4 circle with radius = 10 cm
• Right triangle with hypotenuse = 10 cm, base = 8 cm → height = 6 cm
α = angle in right triangle at O → cosα = 8/10 = 4/5
• Sector with central angle θ, where sinθ = 4/5
18.
a)
Drop perpendicular from B to AD at point E
AD = AE + ED = AE + 7.3
To find AE, use right angle ABE:
cos(58) = AE/4.7
b)
There are a number of ways to do this
Since BC||AD, then ∠ACB = ∠CAD
sin(58) = BE/4.7 = CD/4.7 → CD = ?
tan(∠ACB) = tan(∠CAD) = CD/AD → ∠ACB = ?
or
Using law of cosines in △ABC, we get:
AC² = AB² + BC² - 2(AB)(BC) cos(∠ABC)
Note: you can easily find ∠ABC since you already know 3 of the
angles of the trapezium.
Using law of sines in △ABC, we get:
sin(∠ACB)/AB = sin(∠ABC)/AC → ∠ACB = ?
21.
a)
Probe by AAA
b)
Since Area(BCDE) = Area(ABE), then Area(ACD) = 2 * Area(ABE)
Since ratio of areas of similar triangles = 2, then ratio of sides = √2
AC/AB = √2
(AB+BC)/AB = √2
(AB+3)/AB = √2
AB = ?