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Is my understanding of volume:volume mixtures correct?
If someone asks me to produce 1000 mL of a 7:9 volume to volume dilution of limonene and water,
Is that 7 parts of limonene + 9 parts of water in my volumetric flask = 16 parts in my flask?
Therefore the volume of limonene (L) that I should add is (7 / 16) * 1000 mL = 437.5 mL of Limonene
The volume of water to add is (9 / 16) * 1000 mL = 562.5 mL
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So 562.5 mL of water added to 437.5 mL of limonene makes a 7:9 v/v mixture of limonene and water?
2 Answers
- Trevor HLv 72 years ago
Without getting into the complexities of solubility of limonene and Korean industrial research , Your calculations are correct in principle.
One problem remains - that is the final volume of two solutions when mixed is not always exactly the sum of the two volumes.
In chemistry it is better to calculate the volume of limonene as you have done , and then say - add water to final volume 1000mL. Or possibly a better method is to make a larger theoretical volume , say 1100mL
Measure out 7/16*100 = 481.25mL limonene and 9/16*100 = 618.75 mL water . Measure these out and blend. Do not worry what the volume is. Apply your Korean technology to get a stable mixture. Then measure out exactly 1000mL of what you have. discard any excess.
