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? asked in Science & MathematicsMathematics · 2 years ago

How do I find the values of a and b: 3ax + 6 -4(x+ b) ≡ 11x + 14?

3 Answers

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  • Ash
    Lv 7
    2 years ago
    Favorite Answer

    3ax + 6 -4(x+ b) ≡ 11x + 14

    3ax + 6 - 4x - 4b ≡ 11x + 14

    (3a - 4)x + (6 -4b) ≡ 11x + 14

    As you see, the x coefficients should be same, while the constants should be same

    3a-4 = 11

    3a = 15

    a = 5

    Also

    6-4b = 14

    -4b = 8

    b = -2

    a = 5 and b = -2

  • Como
    Lv 7
    2 years ago

    (3a - 4) x - 4b = 11x + 8

    3a - 4 = 11

    - 4b = 8

    3a = 15

    4b = - 8

    a = 5 , b = - 2

  • Anonymous
    2 years ago

    lhlprfrx

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