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How many total atoms of each indicated element are present in CH3(CH2)14CH3?
3 Answers
- wanszetoLv 72 years ago
In each -CH₃ group, there are 1 C atom and 3 H atoms.
In each -CH₂- group, there are 1 C atom and 2 H atoms.
(-CH₂-)₁₄ means there are 14 -CH₂- groups.
In a molecule of CH₃(CH₂)₁₄CH₃ :
Number of C atoms = 1 + 1×14 + 1 = 16
Number of H atoms = 3 + 2×14 + 3 = 34
- RaymondLv 72 years ago
It is a simple chain of 16 carbons, with 34 hydrogen atoms, all linked together with simple bonds.
Hexadecane
Hexadec- means "six and ten" (for the sixteen -- it is from the Latin)
-ane (in this context) means that the chain of carbon uses only single valence bonds.
To calculate it from the formula you gave us:
C
the first C (the one that has 3 hydrogen atoms tied to it) = 1 C and 3 H
then the middle part of the chain is made up of 14 sets having one carbon and 2 hydrogen each = 14 C and 28 H
The last C has 3 hydrogens = 1 C and 3 H
Add them up.
Source(s): https://en.wikipedia.org/wiki/Hexadecane