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? asked in Science & MathematicsChemistry · 2 years ago

How many total atoms of each indicated element are present in CH3(CH2)14CH3?

3 Answers

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  • 2 years ago

    In each -CH₃ group, there are 1 C atom and 3 H atoms.

    In each -CH₂- group, there are 1 C atom and 2 H atoms.

    (-CH₂-)₁₄ means there are 14 -CH₂- groups.

    In a molecule of CH₃(CH₂)₁₄CH₃ :

    Number of C atoms = 1 + 1×14 + 1 = 16

    Number of H atoms = 3 + 2×14 + 3 = 34

  • 2 years ago

    It is a simple chain of 16 carbons, with 34 hydrogen atoms, all linked together with simple bonds.

    Hexadecane

    Hexadec- means "six and ten" (for the sixteen -- it is from the Latin)

    -ane (in this context) means that the chain of carbon uses only single valence bonds.

    To calculate it from the formula you gave us:

    C

    the first C (the one that has 3 hydrogen atoms tied to it) = 1 C and 3 H

    then the middle part of the chain is made up of 14 sets having one carbon and 2 hydrogen each = 14 C and 28 H

    The last C has 3 hydrogens = 1 C and 3 H

    Add them up.

  • 2 years ago

    16 atoms C

    34 atoms H

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